MySQL
190829_01 기본문
猫猫
2019. 8. 30. 17:24
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USE studyDB;
create table test(id INT);
insert into test values(1);
insert into test values(110);
insert into test values(500);
select * from test;
create table test1(id int primary key not null, name char(10));
insert into test1 (40, 'test');
select * from test1;
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